What is the KVA rating required for a Buck-Boost transformer that can operate a 240-V, 150 A load from a 208-volt supply?

Study for the Independent Electrical Contractors (IEC) Year 2 Part 3 Test. Use flashcards and multiple choice questions with hints and explanations to prepare confidently. Get exam-ready now!

To determine the KVA rating needed for a Buck-Boost transformer that will operate a 240-V, 150 A load from a 208-volt supply, it’s essential to calculate the total power requirement using the formula for apparent power, which is KVA = (Volts x Amperes) / 1000.

First, we calculate the desired output power at 240 volts:

  • Power (P) = Voltage (V) x Current (I)

  • P = 240 V x 150 A = 36,000 VA, or 36 KVA.

Next, to get the KVA, we divide by 1000:

  • KVA = 36,000 VA / 1000 = 36 KVA.

However, this doesn’t consider the differences between the input voltage (208 V) and output voltage (240 V). When using a Buck-Boost transformer, we typically only need to account for the load, which is already known to be 36 KVA due to the voltage and current specifications of the load.

The KVA rating derived matches the demand of the load, ensuring that the transformer can handle the required output without being overloaded. This calculation shows that a 5.0 KVA

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