The power factor for a load is ___% if true power equals 11 kW and apparent power equals 12 kVA.

Study for the Independent Electrical Contractors (IEC) Year 2 Part 3 Test. Use flashcards and multiple choice questions with hints and explanations to prepare confidently. Get exam-ready now!

To find the power factor for a load, you can use the formula:

[ \text{Power Factor (PF)} = \frac{\text{True Power (P)}}{\text{Apparent Power (S)}} ]

In this scenario, the true power is given as 11 kW and the apparent power is 12 kVA.

First, convert the true power to kVA, which is already expressed in kW (11 kW corresponds to 0.1 kVA). The power factor calculation is as follows:

[ \text{PF} = \frac{11 \text{ kW}}{12 \text{ kVA}} = \frac{11}{12} ]

Now, to convert this fraction into a percentage:

[ \text{PF} = \frac{11}{12} \times 100 \approx 91.67% ]

Rounded off, this value gives approximately 91.7%. This indicates that the load is operating effectively, with a good balance between true power and apparent power, which is desirable in electrical systems to ensure efficiency and minimize losses.

Therefore, the correct answer reflects that the power factor, expressed as a percentage, is 91.7%,

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