In a single-phase system, what is the total current drawn by a load if the load’s kVA rating is 17.2?

To determine the total current drawn by a load in a single-phase system from its kVA rating, you can use the formula:

[

\text{Current (I)} = \frac{\text{kVA} \times 1000}{\text{Voltage (V)}}

]

In this case, if we assume a common voltage level (e.g., 120V or 240V), we can proceed to calculate the current based on a kVA rating of 17.2.

For example, at a standard voltage of 240 volts:

[

I = \frac{17.2 \times 1000}{240}

]

[

I = \frac{17200}{240}

]

[

I = 71.67 \text{ amps}

]

However, if you multiply that kVA by a different standard voltage, say 480V, you would get:

[

I = \frac{17.2 \times 1000}{480}

]

[

I = \frac{17200}{480}

]

[

I = 35.83 \text{ amps}

]

For option A suggesting 82.7 amps,