In a circuit with 25 ohms resistance and 50 ohms capacitive reactance, what is the calculated impedance?

Study for the Independent Electrical Contractors (IEC) Year 2 Part 3 Test. Use flashcards and multiple choice questions with hints and explanations to prepare confidently. Get exam-ready now!

To determine the impedance in a circuit that includes both resistance and capacitive reactance, it's essential to use the formula for the impedance of an R-C circuit. The impedance ( Z ) can be calculated using the formula:

[

Z = \sqrt{R^2 + X_C^2}

]

where ( R ) is the resistance, and ( X_C ) is the capacitive reactance.

In this case, the resistance ( R ) is 25 ohms, and the capacitive reactance ( X_C ) is 50 ohms. Plugging these values into the formula gives:

  1. Calculate ( R^2 ):

[

R^2 = 25^2 = 625

]

  1. Calculate ( X_C^2 ):

[

X_C^2 = 50^2 = 2500

]

  1. Add the squared values:

[

R^2 + X_C^2 = 625 + 2500 = 3125

]

  1. Take the square root to find ( Z ):

[

Z = \sqrt{3125} \approx 55.90

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