In a 3Ø, 480-volt system, a 41 KVA load is located 280 feet from the panel. If K=11.3 and using 8 AWG wire, what is the voltage applied to the load?

Study for the Independent Electrical Contractors (IEC) Year 2 Part 3 Test. Use flashcards and multiple choice questions with hints and explanations to prepare confidently. Get exam-ready now!

To determine the voltage applied to the load in a three-phase, 480-volt system, we need to calculate the voltage drop due to the resistance of the wire over the distance from the panel to the load. The K-factor (K = 11.3) is used in the calculation to help find the voltage drop per ampere per 1000 feet of wire.

First, we need to compute the current drawn by the load. For a three-phase system, we can use the following formula to find the current:

[ I = \frac{KVA \times 1000}{\sqrt{3} \times Voltage} ]

Substituting the values:

[ I = \frac{41 \times 1000}{\sqrt{3} \times 480} ]

Calculating this gives us the current flowing through the wire.

Next, we can find the voltage drop using the formula:

[ Voltage Drop = \frac{K \times I \times Length}{1000} ]

where the length is the distance to the load (280 feet in this case).

Substituting the values, we have:

[ Voltage Drop = \frac{11.3 \times I \times 280}{100

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