If the current in the primary of a transformer rated at 120 volts and 16 volts is 1.1 amps, how many amps is drawn by the secondary load?

To solve the problem, we begin by recognizing that a transformer operates based on the principle of power conservation (ignoring losses for this calculation). Power in the primary side of the transformer is equal to the power in the secondary side.

The formula for power (P) in a circuit is given by:

[ P = V \times I ]

where ( V ) is the voltage and ( I ) is the current.

In this scenario, the primary side has a voltage of 120 volts and a current of 1.1 amps. Thus, the power on the primary side can be calculated as:

[ P_{primary} = 120 , \text{volts} \times 1.1 , \text{amps} = 132 , \text{watts} ]

Now, for the secondary side, the voltage is 16 volts, and we need to find the current (I_secondary) flowing through the secondary load. Since power must be conserved in an ideal transformer, we set the power of the secondary side equal to the power of the primary side:

[ P_{secondary} = V_{secondary} \times I_{secondary} ]

Setting the powers equal gives:

[