If a transformer rated at 15 KVA has secondary windings rated for 120/240 volts and several 120-volt loads are connected, what is the maximum current it can supply to those loads?

Study for the Independent Electrical Contractors (IEC) Year 2 Part 3 Test. Use flashcards and multiple choice questions with hints and explanations to prepare confidently. Get exam-ready now!

To determine the maximum current a transformer can supply to its loads, you can use the formula for power in a single-phase system, which is:

Power (in KVA) = Voltage (in Volts) × Current (in Amps) / 1000

In this case, the transformer is rated at 15 KVA, and the secondary voltage for the connected 120-volt loads is 120 volts. Rearranging the formula to solve for current gives us:

Current = Power / Voltage × 1000

Substituting the known values into the formula:

Current = 15 KVA / 120 V × 1000

Current = 15,000 VA / 120 V

Current = 125 Amps

However, since the question specifies that we must consider multiple 120-volt loads connected to a transformer with 240 volts available, it’s important to note that the current at 120 volts needs to be considered for loads connected in parallel. Each individual 120-volt load will draw current, but the total supplied by the transformer will depend on how many loads are actually connected.

If you were focusing solely on a 15 KVA transformer connected at 120 volts, that means each leg can

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