For a 90 KVA, 240-volt motor, how much current will each circuit conductor carry?

To determine the current that each circuit conductor will carry for a 90 KVA, 240-volt motor, you can use the formula:

[ \text{Current (I)} = \frac{\text{Power (P) in KVA} \times 1000}{\text{Voltage (V)}} ]

In this case, the power is 90 KVA and the voltage is 240 volts. Substituting these values into the formula gives:

[ I = \frac{90 \times 1000}{240} ]

Calculating this:

[ I = \frac{90000}{240} ]

[ I = 375 \text{ amperes} ]

Since the motor is typically three-phase, each conductor would carry one-third of the total current. Therefore, divide the total current by 3 to find the current per conductor:

[ \text{Current per conductor} = \frac{375}{3} = 125 \text{ amperes} ]

However, if the question specifically indicates the rating of a single conductor for calculations involving a three-phase system, the answer is approached differently.

Instead of dividing 375 by three, we should consider the need for the full load of