During peak periods, if 100 amps flows through the conductors and 44 amps normally flows with 19.36 kW power loss, what are the I2R losses in the conductors?

To determine the I²R losses in the conductors, it's essential to understand the formula for calculating these losses. The I²R losses, which represent the power lost due to the resistance in the conductors as current flows through them, can be calculated using the formula:

[ \text{I²R losses} = I^2 \times R ]

Where I is the current flowing through the conductors and R is the resistance of those conductors.

In this scenario, peak current loading is observed at 100 amps. If during normal operation 44 amps produces a loss of 19.36 kW, the resistance can be determined as follows:

1. Calculate the resistance:

[ R = \frac{P}{I^2} = \frac{19.36 kW}{(44 , \text{amps})^2} ]

2. Substitute the values:

[ R = \frac{19,360 \text{ watts}}{1936 \text{ (amps)}^2} = 10 , \Omega ]

Now that we know the resistance, we can apply this to calculate the I²R losses at the peak current of 100 amps:

[ \text